Answer: A, C
Isothermal: w=nRTln2=2×8.314×300×0.693=3.46 kJ (statement 1 true). Adiabatic: T2=300×2−2/3=189 K, not 238 K (that uses the exponent 1/3), so statement 2 is false. Then w=nCV(T1−T2)=3×8.314×(111)≈2.77 kJ (statement 3 true). At the same final volume the adiabatic gas is colder, so its pressure is lower, and statement 4 is false.