At 298 K and constant pressure, N2(g) + 3H2(g) -> 2NH3(g) has Delta H=-92.2 kJ. Treating the surroundings as a large reservoir at 298 K, Delta S_surr is

JEE Main levelSingle correct optionDifficulty 2 of 3td141

At $298 K$ and constant pressure, $N X_{2} (g) + 3 H X_{2} (g) 2 NH X_{3} (g)$ has $Δ H = - 92.2 kJ$ . Treating the surroundings as a large reservoir at $298 K$ , $Δ S_{s u rr}$ is

The surroundings receive the heat released by the system at constant

P

q_{s u rr} = - Δ H = + 92200 J

Δ S_{s u rr} = q_{s u rr} / T = 92200/298 = + 309 J K^{- 1}

; the sign is positive because heat flows into the surroundings.