JEE Main levelOne or more correct optionsDifficulty 2 of 3td134
Select the correct statement(s) about standard enthalpy changes at 298K.
AThe standard enthalpy of combustion of graphite equals ΔfH∘(COX2(g)).
BThe standard enthalpy of combustion of HX2(g) to liquid water equals ΔfH∘(HX2O(l)).
CThe standard enthalpy of combustion of graphite equals ΔfH∘(CO(g)).
DΔfH∘(OX3(g)) is zero because it is an element.
Answer: A, B
Burning graphite gives COX2 from elements in their reference states, so ΔcH∘(C)=ΔfH∘(COX2) (statement 1). Likewise HX2+21OX2HX2O(l) is both the combustion of HX2 and the formation of liquid water (statement 2). Graphite burns to COX2, not CO, so statement 3 is false. The reference form of oxygen is OX2, so ΔfH∘(OX3)=0 and statement 4 is false.