Using average bond enthalpies ($\mathrm{H}-\mathrm{H}=436$, $\mathrm{Cl}-\mathrm{Cl}=243$, $\mathrm{H}-\mathrm{Cl}=431\mathrm{kJ}\mathrm{mo}{\mathrm{l}}^{-1}$), the enthalpy change of $\mathrm{H}{}_2(\mathrm{g})+\mathrm{Cl}{}_2(\mathrm{g})\to 2\mathrm{HCl}(\mathrm{g})$ is

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