Answer: A, B, D
Reversible cycle: qh/Th+qc/Tc=0 in sign convention, so ∣qc∣=qhTc/Th=600 J and w=400 J, efficiency 1−300/500=40 percent (A, B true). Entropy changes of reservoirs are −1000/500=−2.0 and +600/300=+2.0 JK−1, total zero (C false). With Tc=200 K: ∣qc∣=1000(200)/500=400 J (D true).