JEE Advanced levelOne or more correct optionsDifficulty 3 of 3td031
A gas mixture contains 1.00mol He and 2.00molOX2 (treat OX2 as a rigid diatomic ideal gas with vibrations frozen; R=8.314Jmol−1K−1). Which statements are correct?
AThe total CV of the mixture is about 54.0JK−1.
BThe γ of the mixture equals 1.40.
CHeating the mixture by 10.0K at constant pressure needs about 540J.
DOn reversible adiabatic compression to half the volume from 300K, the final temperature is about 413K.
Answer: A
CV=1(23R)+2(25R)=6.5R=54.04JK−1 (A true). CP=CV+3R=8.5R, so γ=8.5/6.5=1.462, not 1.40 (B false). Constant-pressure heat for 10K is 8.5R(10)=790J; 540J is the constant-volume value (C false). T2=300×2γ−1=413.1K (D true).