JEE Advanced levelNumerical answerDifficulty 3 of 3sc203
14 mL of oil is dispersed in water as spherical droplets of uniform radius 0.60 micrometre. The oil-water interfacial tension is 0.038 N/m. Neglecting the area of the original bulk oil, calculate the minimum work in joules needed to create the interface (two decimals). Use total area =3V/r for spheres of total volume V.
Numerical answer type, answer in J, tolerance 0.02.
Answer: 2.66 J
For n spheres, nV1=V and area =n⋅4πr2=3V/r. Area =3×14×10−6/(0.60×10−6)=70m2. Work =γA=0.038×70=2.66 J.