A $1.0 g$ sample of a metal catalyst has $1.8 \times 1 0^{19}$ active sites and forms $0.0150 mol$ of product per minute. Calculate the turnover frequency in $s^{- 1}$ (molecules of product per site per second) to the nearest integer. Use $N_{A} = 6.022 \times 1 0^{23} mo l^{- 1}$ .

Numerical answer type, answer in s^-1, tolerance 1.

Answer: 8 s^-1

Molecules of product per second

= 0.0150 \times 6.022 \times 1 0^{23} /60 = 1.506 \times 1 0^{20}

. Dividing by

1.8 \times 1 0^{19}

sites gives TOF

= 8.36 s^{- 1}

, which is 8 to the nearest integer.