In a catalytic hydrogenation, 0.180 mmol of catalyst converts benzene into 33.6 g of cyclohexane (C6H12, M = 84 g mol^-1). Calculate the turnover number (moles of product per mole of catalyst), to the nearest integer.

JEE Main levelNumerical answerDifficulty 2 of 3sc081

In a catalytic hydrogenation, $0.180 mmol$ of catalyst converts benzene into $33.6 g$ of cyclohexane ( $C X_{6} H X_{12}$ , $M = 84 g mo l^{- 1}$ ). Calculate the turnover number (moles of product per mole of catalyst), to the nearest integer.

Numerical answer type, tolerance 1.

Moles of product

= 33.6/84 = 0.400 mol = 400 mmol

. TON

= 400/0.180 = 2222.2

, i.e. 2222.