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JEE Main levelSingle correct optionDifficulty 2 of 3sc069

For an enzyme reaction obeying $v = \frac{V _{ma x} [ S ]}{K _{m} + [ S ]}$ , when $[S] ≫ K_{m}$ the rate is

Afirst order in $[S]$ and independent of enzyme concentration
Balmost independent of $[S]$ and proportional to the total enzyme concentration
Cinversely proportional to $[S]$
Dzero, because all the enzyme is consumed

Answer: B

For

[S] ≫ K_{m}

,

v \to V_{ma x} = k_{c a t} [E]_{t}

. The enzyme is saturated, so the rate is zero order in substrate and proportional to

[E]_{t}

.

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