NEET levelSingle correct optionDifficulty 1 of 3sc009
For the adsorption of a gas on a solid surface, the signs of ΔH and ΔS of the process are, respectively:
AΔH>0 and ΔS>0
BΔH<0 and ΔS>0
CΔH>0 and ΔS<0
DΔH<0 and ΔS<0
Answer: D
Adsorption releases energy, so ΔH<0. Gas molecules lose freedom of motion when held on the surface, so ΔS<0. Spontaneity (ΔG<0) therefore requires ∣ΔH∣>∣TΔS∣.