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NEET levelSingle correct optionDifficulty 1 of 3sc005

The Freundlich adsorption isotherm for a gas on a solid, where $x$ is the mass of gas adsorbed on mass $m$ of adsorbent at pressure $p$ , is:

A $\frac{x}{m} = k p^{n}$
B $\frac{x}{m} = k p^{1/ n}$
C $\frac{x}{m} = \frac{k}{p ^{1/ n}}$
D $\frac{x}{m} = k lo g p$

Answer: B

The empirical Freundlich relation is

x / m = k p^{1/ n}

with

n > 1

for a gas. Taking logarithms gives

lo g (x / m) = lo g k + \frac{1}{n} lo g p

.

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