Answer: C
2,4-DNP is positive for aldehydes and ketones only. A (pentan-2-one) is a methyl ketone and so gives iodoform. B (pentanal) is an aldehyde and gives a silver mirror. D (ethyl acetate) is an ester and gives no 2,4-DNP precipitate. C (pentan-3-one) is a ketone without CHX3COX−, so it satisfies all three conditions.