Answer: A, B, D
The compound shown is 4-hydroxybenzaldehyde: CHO, OH and two aromatic sets, 4 signals. Methylation gives 4-methoxybenzaldehyde with CHO, OCHX3 and two aromatic sets, 4 signals (not 5). Nitration ortho to OH gives 4-hydroxy-3-nitrobenzaldehyde with CHO, OH and three different aromatic H: 5 signals.