Benzenediazonium chloride is prepared from aniline with NaNO2/HCl at 273 K. Which of the following transformations of this salt are correct?

Warming with water gives phenol.

Warming with aqueous NaOH gives aniline.

JEE Main levelOne or more correct optionsDifficulty 2 of 3si207

Benzenediazonium chloride is prepared from aniline with $NaNO X_{2} / HCl$ at 273 K. Which of the following transformations of this salt are correct?

The Sandmeyer reaction with

CuCl / HCl

gives chlorobenzene. Hypophosphorous acid reduces the diazonium group to H, giving benzene. Warming with water replaces

N X_{2} X^{+}

by OH, giving phenol. The reverse conversion to aniline does not occur, so (D) is wrong.