Answer: B, C, D
Oxidation to terephthalic acid shows two para side chains. The iodoform and DNP tests identify a methyl ketone, so X is p-CHX3−CX6HX4−COCHX3 (4-methylacetophenone, CX9HX10O). Clemmensen gives 1-ethyl-4-methylbenzene, and the haloform reaction converts COCHX3 into COOH, giving 4-methylbenzoic acid. X has no O-H group, only a C=O stretch near 1685 cm−1.