Answer: A, C, D
1,2-Dimethylcyclobutane: cis is meso and trans is a pair of enantiomers, so 3 stereoisomers. 1,3-Dimethylcyclobutane: C1 and C3 are not stereocentres (two identical CHX2 paths); cis and trans exist but both have a mirror plane through C1 and C3, so 2 achiral stereoisomers and no enantiomers. 1,1-Dimethylcyclobutane: 1 form only. Total = 3 + 2 + 1 = 6.