The compound shown is acetaldehyde oxime, $\mathrm{CH}{}_3\mathrm{CH}=\mathrm{NOH}$, drawn with a definite geometry about the $\mathrm{C}=\mathrm{N}$ bond. Its configuration is

On carbon the groups are $\mathrm{CH}{}_3$ (priority) and $\mathrm{H}$. On nitrogen the groups are $\mathrm{OH}$ and the lone pair; the lone pair always has the lowest priority, so $\mathrm{OH}$ is the higher group. In the drawing $\mathrm{CH}{}_3$ and $\mathrm{OH}$ lie on opposite sides of the $\mathrm{C}=\mathrm{N}$ bond, so the oxime shown is $(E)$. Oximes and imines show $E/Z$ isomerism exactly like alkenes because of the lone pair.