Answer: A
A 0∘ dihedral puts the two methyls on top of each other (fully eclipsed, highest energy). At 60∘ the groups are staggered and close (gauche). At 120∘ the CH3 groups are eclipsed with H atoms (partially eclipsed, anticlinal). At 180∘ they are staggered and opposite (anti, lowest energy). So P-3, Q-2, R-4, S-1.