Answer: A
(P) Two identical substituents on adjacent carbons: cis (meso) plus the trans pair gives 3. (Q) 1,3-Dimethylcyclobutane has a mirror plane in both cis and trans isomers, so only 2. (R) Two different substituents and two stereocentres give 22=4. (S) Chlorocyclobutane has no stereocentre, so 1. The match is P-3, Q-2, R-4, S-1.