MolSynapsequestion bank
MolSynapse / Question bank / Stereoisomerism / Conformational analysis of ethane, butane and cyclohexane
JEE Advanced levelSingle correct optionDifficulty 3 of 3st162

In the Newman projection along C2-C3 of butane, the anti conformer has front at 12 o'clock and rear at 6 o'clock. The rear carbon is rotated by so that rear groups move to 8, 4 and 12 o'clock (the rear now at 8). Using eclipsing energies H/H 4.0, H/ 6.0, and gauche 3.8 kJ/mol above anti, the energy barrier for the gauche-to-anti conversion through this eclipsed conformer is

  1. A
  2. B
  3. C
  4. D

Answer: C

Rear groups are CH3 at 8, H at 4 and H at 12 (the originals at 6, 2 and 10 moved by two hours). Eclipsed pairs: front CH3 (12) with rear H (12) = 6.0; front H (4) with rear H (4) = 4.0; front H (8) with rear CH3 (8) = 6.0. Energy = 16.0 above anti. This is the transition state between anti and the gauche conformer (rear CH3 at 10), so the gauche-to-anti barrier = 16.0 - 3.8 = 12.2 kJ/mol; 16.0 is the anti-to-gauche barrier.
Practice Stereoisomerism More on Conformational analysis of ethane, butane and cyclohexane

More questions on Conformational analysis of ethane, butane and cyclohexane