Answer: A, B, D
For (R,R), C2 has Br on the left and C3 has Br on the right, so the Br atoms are on opposite sides. In the eclipsed Fischer conformer, groups on opposite sides are 120∘ apart (not 0∘, which applies to same-side groups). Interchanging Br and H at C3 changes (R,R) to (R,S), the meso diastereomer.