Answer: A
All groups are eclipsed (dihedral 0∘ pairs at 12, 4 and 8 o'clock). At 12 o'clock front CHX3 meets rear H (6.0), at 4 o'clock front H meets rear CHX3 (6.0), and at 8 o'clock H meets H (4.0). The total is 6.0+6.0+4.0=16 kJ/mol. The case with the two methyls eclipsed (19 kJ/mol) does not apply here.