A compound CH3-CH(OH)-CHBr-CHCl-CH3 is drawn. Assuming no symmetry, how many stereoisomers does it have?

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NEET levelSingle correct optionDifficulty 1 of 3st060

A compound $CH X_{3} - CH (OH) - CHBr - CHCl - CH X_{3}$ is drawn. Assuming no symmetry, how many stereoisomers does it have?

Answer: A

The three stereocentres are C2, C3 and C4, and all carry four different groups. The chain is unsymmetrical (OH, Br and Cl are all different), so no meso form arises. The number is

2^{3} = 8

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A compound CHX3​−CH(OH)−CHBr−CHCl−CHX3​ is drawn. Assuming no symmetry, how many stereoisomers does it have?

Answer: A

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A compound $CH X_{3} - CH (OH) - CHBr - CHCl - CH X_{3}$ is drawn. Assuming no symmetry, how many stereoisomers does it have?