Answer: C, D
C2: Cl>COOH>C3>H (COOH has (O,O,O), C3 has (O,C,H)). Cl (left) → COOH (top) → C3 (bottom) is clockwise; H is horizontal, so reverse: S. C3: OH>C4 (Br,C,H)>C2 (Cl,C,H)>H. OH (left) → C4 (bottom) → C2 (top) is anticlockwise; reverse: R. C4: Br>C3>CHX3>H; Br (left) → C3 (top) → CHX3 (bottom) is clockwise; reverse: S. So the compound is (2S,3R,4S): B and C are correct; A is wrong and C2 and C3 differ (D wrong).