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NEET levelSingle correct optionDifficulty 1 of 3st004

Which of the following shows syn/anti (geometrical) isomerism about the $C = N$ bond?

AAcetaldoxime, $CH X_{3} - CH = N - OH$
BFormaldoxime, $CH X_{2} = N - OH$
CAcetone oxime, $(CH X_{3}) X_{2} C = N - OH$
DAcetone, $CH X_{3} - CO - CH X_{3}$

Answer: A

In an oxime the nitrogen carries

OH

and a lone pair, which are different, so the carbon must carry two different groups. Acetaldoxime has

H

and

CH X_{3}

on carbon and shows isomerism. Acetone oxime has two

CH X_{3}

and formaldoxime has two

H

, so neither does; acetone has no

C = N

.

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