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For a solution of a non-volatile solute in a volatile solvent, Raoult's law states that the relative lowering of vapour pressure, $\frac{p ^{0} - p}{p ^{0}}$ , is equal to the

Amolarity of the solute
Bmole fraction of the solvent
Cmole fraction of the solute
Dmolality of the solute

Answer: C

Raoult's law for a non-volatile solute gives

p = x_{1} p^{0}

, where

x_{1}

is the mole fraction of the solvent. Hence

\frac{p ^{0} - p}{p ^{0}} = 1 - x_{1} = x_{2}

, the mole fraction of the solute. Molality and molarity are not the quantity that appears in the law.

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