JEE Main levelNumerical answerDifficulty 2 of 3so100
A 0.50m aqueous solution of a salt ABX2 (giving three ions per formula unit, i=1+2α) freezes at −1.395∘C. Take Kf=1.86Kkgmol−1. Find the degree of dissociation α (two decimal places).
Numerical answer type, tolerance 0.01.
Answer: 0.25
i=ΔTf/(Kfm)=1.395/(1.86×0.50)=1.50. From i=1+2α, α=(1.50−1)/2=0.25.