Find the osmotic pressure of a $0.25 mol L^{- 1}$ solution of a non-electrolyte at $298 K$ in $kPa$ (nearest integer). Use $R = 8.314 J mo l^{- 1} K^{- 1}$ and note that $1 L = 1 0^{- 3} m^{3}$ .

Numerical answer type, answer in kPa, tolerance 1.

Answer: 619 kPa

Concentration

= 0.25 mol L^{- 1} = 250 mol m^{- 3}

π = c RT = 250 \times 8.314 \times 298 = 619393 Pa = 619.4 kPa