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JEE Advanced levelSingle correct optionDifficulty 3 of 3ss214

The ions $Cu X^{2 +}$ , $Cr X^{3 +}$ , $Fe X^{2 +}$ (high spin) and $Mn X^{2 +}$ (high spin) are arranged in increasing order of their spin-only magnetic moment. The correct order is

A $Cu X^{2 +} < Cr X^{3 +} < Fe X^{2 +} < Mn X^{2 +}$
B $Cr X^{3 +} < Cu X^{2 +} < Fe X^{2 +} < Mn X^{2 +}$
C $Cu X^{2 +} < Cr X^{3 +} < Mn X^{2 +} < Fe X^{2 +}$
D $Mn X^{2 +} < Fe X^{2 +} < Cr X^{3 +} < Cu X^{2 +}$

Answer: A

Unpaired electrons:

Cu X^{2 +}

(

d^{9}

) 1,

Cr X^{3 +}

(

d^{3}

) 3,

Fe X^{2 +}

(

d^{6}

) 4,

Mn X^{2 +}

(

d^{5}

) 5. With

μ = n (n + 2)

: 1.73, 3.87, 4.90, 5.92 BM. The order follows.

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