An element of molar mass 130 g mol^-1 crystallises in a simple cubic lattice with edge 360 pm. Use N_A = 6.022x10^23 mol^-1. Calculate its density in g cm^-3 (two decimals).

JEE Main levelNumerical answerDifficulty 2 of 3ss156

An element of molar mass $130 g mo l^{- 1}$ crystallises in a simple cubic lattice with edge $360 pm$ . Use $N_{A} = 6.022 \times 1 0^{23} mo l^{- 1}$ . Calculate its density in $g c m^{- 3}$ (two decimals).

Numerical answer type, answer in g/cm^3, tolerance 0.03.

Z = 1

for a simple cubic cell.

ρ = \frac{130}{6.022 \times 1 0 ^{23} \times ( 3.60 \times 1 0 ^{- 8} ) ^{3}} = 4.63 g c m^{- 3}