MolSynapse
question bank
All chapters
NEET
JEE
Practice
MolSynapse
/
Question bank
/
Solid State
/
Cubic unit cells: packing efficiency and density
JEE Main level
Single correct option
Difficulty 2 of 3
ss062
Iron is bcc with edge length
287
pm
in one of its forms. Taking
3
=
1.732
, the radius of an iron atom in pm is
A
143.5
B
101.5
C
124.3
D
248.5
Answer: C
Atoms touch along the body diagonal, so
4
r
=
3
a
and
r
=
3
a
/4
=
1.732
×
287/4
=
124.3
pm
.
Practice Solid State
More on Cubic unit cells: packing efficiency and density
Previous question
Next question
More questions on Cubic unit cells: packing efficiency and density
What is the coordination number of an atom in a simple cubic lattice?
NEET level
A metal of atomic mass 64 g mol^-1 crystallises in a face-centred cubic lattice with edge length 360 pm. Its density in g cm^-3 is (take N_A...
JEE Main level
A metal crystallises in an fcc lattice and its atomic radius is 128 pm. Taking sqrt2=1.414, the edge length of the unit cell in pm is
JEE Main level
A cubic ionic solid of formula mass 58.5 g mol^-1 has edge length 564 pm and density 2.16 g cm^-3. Using N_A = 6.022x10^23 mol^-1, the numbe...
JEE Main level
Copper crystallises in an fcc lattice with edge length 361 pm. Taking the atomic mass of Cu as 63.5 and N_A = 6.022x10^23 mol^-1, calculate ...
JEE Main level
Sodium (atomic mass 23) is bcc and has density 0.97 g cm^-3. Using N_A = 6.022x10^23 mol^-1, find the edge length of its unit cell in pm (ne...
JEE Main level