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JEE Main levelNumerical answerDifficulty 2 of 3ss018

Using the spin-only formula $μ = n (n + 2) BM$ , calculate the magnetic moment of the high-spin $Fe X^{2 +}$ ion present in a crystal (two decimals).

Numerical answer type, answer in BM, tolerance 0.02.

Answer: 4.9 BM

Fe X^{2 +}

is

3 d^{6}

; in the high-spin state the electrons are arranged

t_{2 g}^{4} e_{g}^{2}

so

n = 4

unpaired electrons. Hence

μ = 4 \times 6 = 24 = 4.90 BM

.

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