Pure solid NaHCO3 weighing 25.0 g is heated until it is completely converted into Na2CO3 (atomic masses: Na 23, C 12, O 16, H 1). The total loss in mass of the solid is (fill in the value) g (give the answer to two decimal places).

JEE Main levelNumerical answerDifficulty 2 of 3sb194

Pure solid $NaHCO X_{3}$ weighing 25.0 g is heated until it is completely converted into $Na X_{2} CO X_{3}$ (atomic masses: Na 23, C 12, O 16, H 1). The total loss in mass of the solid is (fill in the value) g (give the answer to two decimal places).

Numerical answer type, answer in g, tolerance 0.01.

The reaction is

2 NaHCO X_{3} Na X_{2} CO X_{3} + CO X_{2} + H X_{2} O

. Two moles (

168

g) lose

44 + 18 = 62

g. For 25.0 g the loss is

25.0 \times 62/168 = 9.2262

g, i.e. 9.23 g.