JEE Advanced levelSingle correct optionDifficulty 3 of 3sb163
A 25.0g sample of impure limestone loses 9.68g on strong heating (only CaCOX3 decomposes; the impurities are inert and non-volatile). All the quicklime obtained is slaked with excess water. Molar masses: CaCOX3 100, CaO 56, Ca(OH)X2 74 g/mol. The mass of Ca(OH)X2 formed is:
A12.32g
B18.50g
C16.28g
D22.00g
Answer: C
CaCOX3CaO+COX2: 9.68 g COX2 is 9.68/44 = 0.22 mol, so 0.22 mol CaO forms. CaO+HX2OCa(OH)X2 then gives 0.22 mol, i.e. 0.22 × 74 = 16.28 g. Assuming the sample were pure limestone would wrongly give 18.50 g.