When gypsum is heated at 393 K it forms plaster of Paris, (CaSO4)2.H2O. The number of moles of water lost per mole of gypsum is

JEE Main levelSingle correct optionDifficulty 2 of 3sb089

When gypsum is heated at 393 K it forms plaster of Paris, $(CaSO X_{4}) X_{2} \cdot H X_{2} O$ . The number of moles of water lost per mole of gypsum is

2 CaSO X_{4} \cdot 2 H X_{2} O (CaSO X_{4}) X_{2} \cdot H X_{2} O + 3 H X_{2} O

: two moles of gypsum lose three moles of water. Per mole of gypsum the loss is

3/2 = 1.5

mol.