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JEE Advanced levelOne or more correct optionsDifficulty 3 of 3sb053

The ion product of liquid ammonia, $[NH X_{4} X^{+}] [NH X_{2} X^{-}]$ , is about $1 \times 1 0^{- 30}$ at $223 K$ . Which of the following statements are correct?

AIn pure liquid ammonia $[NH X_{4} X^{+}] = 1 \times 1 0^{- 15} M$ .
B $NH X_{4} Cl$ acts as an acid in liquid ammonia.
C $NaNH X_{2}$ acts as a base in liquid ammonia.
DA neutral solution in liquid ammonia has $pN H_{4} = 7$ .

Answer: A, B, C

Autoionisation is

2 NH X_{3} NH X_{4} X^{+} + NH X_{2} X^{-}

. In the pure solvent

[NH X_{4} X^{+}] = [NH X_{2} X^{-}] = 1 0^{- 30} = 1 0^{- 15} M

, so neutrality corresponds to

pN H_{4} = 15

and not 7.

NH X_{4} X^{+}

raises

[NH X_{4} X^{+}]

(acid) and

NH X_{2} X^{-}

raises

[NH X_{2} X^{-}]

(base).

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