The compound shown is heated with aqueous $\mathrm{NaOH}$ (excess), then acidified with $\mathrm{H}{}_3\mathrm{O}{}^{+}$. Select ALL correct statements.

The compound is phenyl acetate. Saponification cleaves the acyl-oxygen bond: acetate and phenoxide form, and the phenol (pKa about 10) is deprotonated by a second mole of $\mathrm{NaOH}$, so 2 mol of base are used. Acidification liberates ethanoic acid and phenol. No methanol is involved because the alkoxy part is phenol, not a methyl group.