Answer: D
The compound is pent-3-yn-1-ol. Lindlar reduction gives (Z)-pent-3-en-1-ol. Jones reagent oxidises a primary alcohol all the way to the carboxylic acid, giving (Z)-pent-3-enoic acid. Using PCC would stop at the aldehyde, Na/NHX3 would give E, and omitting the first step leaves the alkyne.