Open-chain glucose, CH2OH-(CHOH)4-CHO, is treated with an excess of HIO4. The number of moles of HIO4 consumed per mole of glucose is

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Open-chain glucose, $CH X_{2} OH - (CHOH) X_{4} - CHO$ , is treated with an excess of $HIO X_{4}$ . The number of moles of $HIO X_{4}$ consumed per mole of glucose is

Answer: A

There are six carbons in an unbranched chain, so there are five C-C bonds. Each bond joins two carbons carrying an oxygen function (OH or CHO), so every one is cleaved, consuming five moles of HIO4 and giving five HCOOH and one HCHO.

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Open-chain glucose, CHX2​OH−(CHOH)X4​−CHO, is treated with an excess of HIOX4​. The number of moles of HIOX4​ consumed per mole of glucose is

Answer: A

More questions on Periodic acid and lead tetraacetate cleavage

Open-chain glucose, $CH X_{2} OH - (CHOH) X_{4} - CHO$ , is treated with an excess of $HIO X_{4}$ . The number of moles of $HIO X_{4}$ consumed per mole of glucose is