Answer: B
An electron-donating group such as OMe stays on a carbon that remains sp2, because the radical anion is protonated at positions that avoid placing negative charge next to the donor. The product is therefore the 1,4-diene in which C-1 bearing OMe is a double-bond carbon. The 3-methoxy isomer has OMe on an sp3 carbon, and the conjugated diene is not a Birch product.