tert-Butyl cyclohexyl ketone, $(CH X_{3}) X_{3} C - CO - C X_{6} H X_{11}$ ( $C X_{6} H X_{11}$ = cyclohexyl), is treated with mCPBA. The product is then reduced with $LiAlH X_{4}$ followed by $H X_{3} O X^{+}$ . The two alcohols obtained are

Answer: D

The tertiary tert-butyl group migrates in preference to the secondary cyclohexyl group, giving the ester

C X_{6} H X_{11} - CO - O - C (CH X_{3}) X_{3}

(tert-butyl cyclohexanecarboxylate).

LiAlH X_{4}

cleaves an ester into two alcohols: the acyl part becomes cyclohexylmethanol, and the alkoxy part gives 2-methylpropan-2-ol.