Ethanol is completely oxidised to ethanoic acid by excess acidified K2Cr2O7. Which statements are correct? (Cr goes from +6 to +3.)

The oxidation state of the carbinol carbon changes from -1 to +3 in the organic product's carboxyl carbon.

Four electrons are lost per molecule of ethanol.

Ethanal is an intermediate in the process.

The oxidation state of the carbinol carbon changes from -1 to +3 in the organic product's carboxyl carbon.

Four electrons are lost per molecule of ethanol.

Ethanal is an intermediate in the process.

One mole of K2Cr2O7 oxidises 3 mol of ethanol to the acid.

JEE Main levelOne or more correct optionsDifficulty 2 of 3ro062

Ethanol is completely oxidised to ethanoic acid by excess acidified $K X_{2} Cr X_{2} O X_{7}$ . Which statements are correct? (Cr goes from +6 to +3.)

AThe oxidation state of the carbinol carbon changes from $- 1$ to $+ 3$ in the organic product's carboxyl carbon.
BFour electrons are lost per molecule of ethanol.
CEthanal is an intermediate in the process.
DOne mole of $K X_{2} Cr X_{2} O X_{7}$ oxidises 3 mol of ethanol to the acid.

The carbinol carbon of

CH X_{3} CH X_{2} OH

- 1

and the carboxyl carbon of

CH X_{3} COOH

+ 3

, so 4 electrons are lost, passing through ethanal (

+ 1

). One

Cr X_{2} O X_{7} X^{2 -}

accepts

6 e^{-}

, so it oxidises

6/4 = 1.5

mol of ethanol, not 3 mol. Statements 1, 2 and 3 are correct.