Use Fe = 56, Na = 23, S = 32, C = 12, O = 16. An equimolar mixture of FeSO4 and Na2C2O4 has total mass 2.86 g. It is dissolved in dilute H2SO4 and titrated with 0.04 M KMnO4 (to Mn^2+; Fe^2+ -> Fe^3+, oxalate -> CO2). The volume of KMnO4 required is:

JEE Advanced levelSingle correct optionDifficulty 3 of 3rx144

Use Fe = 56, Na = 23, S = 32, C = 12, O = 16. An equimolar mixture of $FeSO X_{4}$ and $Na X_{2} C X_{2} O X_{4}$ has total mass $2.86 g$ . It is dissolved in dilute $H X_{2} SO X_{4}$ and titrated with $0.04 M$ $KMnO X_{4}$ (to $Mn X^{2 +}$ ; $Fe X^{2 +} Fe X^{3 +}$ , oxalate $CO X_{2}$ ). The volume of $KMnO X_{4}$ required is:

Let each be

x

mol:

152 x + 134 x = 2.86

, so

x = 0.01

. Equivalents

= x (1) + x (2) = 0.03

N (KMnO X_{4}) = 0.04 \times 5 = 0.2

, so

V = 0.03/0.2 = 150 mL