Chlorine disproportionates in hot alkali: 3Cl2 + 6OH- -> 5Cl- + ClO3- + 3H2O. Taking Cl = 35.5, the equivalent mass of Cl2 in this reaction is:

JEE Main levelSingle correct optionDifficulty 2 of 3rx127

Chlorine disproportionates in hot alkali: $3 Cl X_{2} + 6 OH X^{-} 5 Cl X^{-} + ClO X_{3} X^{-} + 3 H X_{2} O$ . Taking Cl = 35.5, the equivalent mass of $Cl X_{2}$ in this reaction is:

Per 3

Cl X_{2}

, 5 electrons are lost (one Cl to

+ 5

) and 5 gained (five Cl to

- 1

). So

n

-factor of

Cl X_{2}

= 5/3

. Equivalent mass

= 71/ (5/3) = 42.6