Hot concentrated alkali converts chlorine as 3Cl2 + 6OH^- -> 5Cl^- + ClO3^- + 3H2O. Select ALL correct statements.

Five out of every six Cl atoms are reduced

3 H2O molecules are formed for every 3 Cl2 consumed

Five out of every six Cl atoms are reduced

10 electrons are transferred in the equation as written

3 H2O molecules are formed for every 3 Cl2 consumed

OH^- acts as the reducing agent

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JEE Advanced levelOne or more correct optionsDifficulty 3 of 3rx089

Hot concentrated alkali converts chlorine as $3 Cl X_{2} + 6 OH X^{-} 5 Cl X^{-} + ClO X_{3} X^{-} + 3 H X_{2} O$ . Select ALL correct statements.

AFive out of every six Cl atoms are reduced
B10 electrons are transferred in the equation as written
C3 $H X_{2} O$ molecules are formed for every 3 $Cl X_{2}$ consumed
D $OH X^{-}$ acts as the reducing agent

Answer: A, C

Of 6 Cl atoms, 5 go 0 to -1 (reduced) and 1 goes 0 to +5 (oxidised), so statement 1 is true. The electrons transferred are 5 (5 x 1 gained = 1 x 5 lost), not 10, so statement 2 is false. The equation shows 3

H X_{2} O

(statement 3 true).

OH X^{-}

only provides the medium;

Cl X_{2}

is both oxidised and reduced, so statement 4 is false.

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Hot concentrated alkali converts chlorine as 3ClX2​+6OHX−​5ClX−+ClOX3​X−+3HX2​O. Select ALL correct statements.

Answer: A, C

More questions on Oxidising and reducing agents, disproportionation

Hot concentrated alkali converts chlorine as $3 Cl X_{2} + 6 OH X^{-} 5 Cl X^{-} + ClO X_{3} X^{-} + 3 H X_{2} O$ . Select ALL correct statements.