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JEE Main levelSingle correct optionDifficulty 2 of 3rx014

Match the species in List I with the oxidation number of the underlined (first-named) element in List II, using the electronegativity order . List I: (P) Cl in , (Q) I in , (R) Br in , (S) I in . List II: (1) , (2) , (3) , (4) .

  1. AP-1, Q-2, R-3, S-4
  2. BP-2, Q-1, R-4, S-3
  3. CP-2, Q-1, R-3, S-4
  4. DP-3, Q-1, R-2, S-4

Answer: C

F is , so Cl in is , Br in is and I in is . In , Cl is more electronegative so I is . The matching is P-2, Q-1, R-3, S-4.
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