JEE Main levelSingle correct optionDifficulty 2 of 3rx014
Match the species in List I with the oxidation number of the underlined (first-named) element in List II, using the electronegativity order F>Cl>Br>I. List I: (P) Cl in ClFX3, (Q) I in ICl, (R) Br in BrFX5, (S) I in IFX7. List II: (1) +1, (2) +3, (3) +5, (4) +7.
AP-1, Q-2, R-3, S-4
BP-2, Q-1, R-4, S-3
CP-2, Q-1, R-3, S-4
DP-3, Q-1, R-2, S-4
Answer: C
F is −1, so Cl in ClFX3 is +3, Br in BrFX5 is +5 and I in IFX7 is +7. In ICl, Cl is more electronegative so I is +1. The matching is P-2, Q-1, R-3, S-4.