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NEET levelSingle correct optionDifficulty 1 of 3rx010

The oxidation number of carbon in chloroform, $CHCl X_{3}$ , is

A $0$
B $+ 2$
C $+ 4$
D $- 2$

Answer: B

Cl is more electronegative than C and H is

+ 1

. So

x + 1 + 3 (- 1) = 0

gives

x = + 2

.

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