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NEET levelSingle correct optionDifficulty 1 of 3rx005

The oxidation number of iron in $K X_{4} [Fe (CN) X_{6}]$ is

A $+ 2$
B $+ 3$
C $+ 4$
D $+ 6$

Answer: A

The complex ion is

[Fe (CN) X_{6}] X^{4 -}

because four

K X^{+}

balance it. So

x + 6 (- 1) = - 4

and

x = + 2

. Choosing

+ 3

confuses it with

K X_{3} [Fe (CN) X_{6}]

.

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