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JEE Main levelSingle correct optionDifficulty 2 of 3rg214

The second virial coefficient of a gas at $T_{1}$ is $- 150 mL mo l^{- 1}$ and at $T_{2}$ is $- 30 mL mo l^{- 1}$ . Which statement is correct?

A $T_{1}$ is greater than $T_{2}$
B $T_{2}$ is greater than $T_{1}$
CBoth temperatures are above the Boyle temperature
DThe gas is ideal at $T_{2}$

Answer: B

B = b - a / RT

rises toward

b

as

T

increases. The less negative value

- 30 mL mo l^{- 1}

corresponds to the higher temperature, so

T_{2}

is greater than

T_{1}

. Both are below

T_{B}

because

B

is still negative.

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